An astronaut is looking down on earth's surface from a space shuttle an altitude of 400 km Assuming that the astronaut's pupil diameter is 5 mm and the wavelength of visible light is 500 nm, the astronaut will be able to resolve linear objects of the size of about :

0.5m

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50m

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500m

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Solution

The correct option is C 50m
The resolving power of an instrument is given by the formula, $R . P = 1.22 \times \frac{λ D}{d}$
Here, d is aperture of the instruments, D is distance of satellite from the earth. Here eye is the optical instruments.
$R . P = \frac{1.22 \times 500 \times 10^{- 9}}{5 \times 10^{- 3}} \times 400 \times 1000$
$= 1.22 \times \frac{10^{- 2}}{10^{- 3}} \times 4 = 1.22 \times 40 = 50 m$

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An astronaut is looking down on earth's surface from a space shuttle an altitude of 400 km Assuming that the astronaut's pupil diameter is 5 mm and the wavelength of visible light is 500 nm, the astronaut will be able to resolve linear objects of the size of about :

The correct option is C 50mThe resolving power of an instrument is given by the formula, R.P=1.22×λDdHere, d is aperture of the instruments, D is distance of satellite from the earth. Here eye is the optical instruments.R.P=1.22×500×10−95×10−3×400×1000 =1.22×10−210−3×4=1.22×40=50m