An astronaut jumps from an airplane. After he had fallen $40 m$ , then his parachute opens. Now he falls with a retardation of $2 m / s^{2}$ and reaches the earth with a velocity of $3.0 m / s$ . What was the height of the aeroplane? (in m)

185

No worries! We‘ve got your back. Try BYJU‘S free classes today!

190

No worries! We‘ve got your back. Try BYJU‘S free classes today!

234

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

200

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C $234$
Velocity after falling through 40m= $\sqrt{2 g h} = \sqrt{2 \times 9. 81 \times 40} = 28 m / s$
Distance travelled after opening the parachute= $(28^{2} - 3^{2}) / 2 \times 2 = 194$
So, height of the aeroplane $= 194 + 40 = 234 m$

Hence none of the above options are correct.

Suggest Corrections

Similar questions

an astronaut jumps from a plane after he had fallen 40 m then his parachute opens now he falls with retardation of 2m/s² reaches the earth with a velocity of 3m/s what's the height of the airplane? How long Astronaut remain in air? g= 9.8m/s^2a

Q. An astronaut jumps from an airplane. After he has fallen 20 m, his parachute opens. Now he
falls with a retardation of 2 m/s2 and reaches the earth with a velocity of 4.0 m/s. What was the initial height of the airplane? Take „g‟ as 10 m/s2.

Q. A parachutist drops first freely from an airplane for

10 s

and then the parachute opens out. Now he descends with net retardation of

2.5 m / s^{2}

. If he bails out of the plane at a height of

2495 m

and

g = 10 m / s^{2}

, his velocity on reaching the ground will be

Q. A parachutist drops first freely from an aeroplane for

10 s

and then parachute opens out. Now he descends with a net retardation of

2.5 {m/s}^{2}

. If he bails out of the plane at a height of

2495 m

and

g = 10 {m/s}^{2}

, his velocity on reaching the ground in

m/s

will be

A parachutist drops first freely from an aeroplane for 10s and then parachute opens out. Now he descends with a net retardation of 2.5 m/ $s^{2}$ . If he falls out of the plane at a height of 2495 m and g=10 m/ $s^{2}$ , his velocity on reaching the ground will be

Join BYJU'S Learning Program

An astronaut jumps from an airplane. After he had fallen 40m, then his parachute opens. Now he falls with a retardation of 2m/s2 and reaches the earth with a velocity of 3.0m/s. What was the height of the aeroplane? (in m)

The correct option is C 234Velocity after falling through 40m=√2gh=√2×9.81×40=28m/sDistance travelled after opening the parachute=(282−32)/2×2=194So, height of the aeroplane=194+40=234mHence none of the above options are correct.

An astronaut jumps from an airplane. After he had fallen $40 m$ , then his parachute opens. Now he falls with a retardation of $2 m / s^{2}$ and reaches the earth with a velocity of $3.0 m / s$ . What was the height of the aeroplane? (in m)