An astronomical telescope has an eye piece of focal length 30 mm. In normal adjustment the separation between lenses is 540 mm, then, angular magnification of the telescope under consideration is
A
18
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B
19
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C
17
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D
11
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Solution
The correct option is C 17 fo+fe=540 mm fo=540−fe=540−30=510 mm m=fofe=51030=17