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Question

An astronomical telescope is to be designed to have a magnifying power of 50 in normal adjustment. If the length of the tube is 102 cm, find the powers of the objective and the eyepiece.

A
10;100
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B
1;50
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C
10;500
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D
2;100
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Solution

The correct option is B 1;50


Magnifying power of an astronomical telescope is given by

m=f0fe=50
f0=50fe --- (1)

Length of the tube
L=f0+fe=102 cm --- (2)

Substituting (1) in (2),
51fe=102
i.e fe=2 cm
and fo=100 cm

Power of objective Po=1fo=1 D
Power of eyepiece Pe=1fe=50 D

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