An athlete completes one round of a circular track of radius R in 40 sec. What will be the magnitude of displacement at the end of 2 min 20 sec?
A
Zero
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B
2R
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C
2πR
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D
7πR
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Solution
The correct option is B2R Total time of motion is 2 min 20 sec = 140 sec
Time period of circular motion = 40 sec
In 140 sec. athlete will complete=2πR40×140=3.5(2πR)=3.5revolutions
So, he will be at diametrically opposite point i.e. Displacement =2R.