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Enthalpy

An athlete is...

Question

An athlete is given 100 g glucose of energy equivalent to 1560 kJ. He utilizes 50% of this gained energy in an event. Enthalpy of $H_{2} O$ for evaporation is $44 k J m o l^{- 1}$ . In order to avoid storage of energy in the body, the mass of water (in g) he would need to perspire is _________.

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Solution

The energy provided to the athlete by consuming 100 g glucose $= 1560 k J$

Energy utilized in event $= \frac{50}{100} \times 1560 = 780 k J$

$∴$ Energy left as excess in body $= 1560 - 780 = 780 k J$

$∵$ 44 kJ energy needed to evaporate 18 g $H_{2} O$

$∴$ 780 kJ energy needed to evaporate $\frac{(18 \times 780)}{44} g H_{2} O = 319.09 g H_{2} O$

Therefore, the athlete should perspire $319.09 g H_{2} O$ in order to avoid any storage of energy in the body.

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