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Enthalpy of Combustion

An athlete is...

Question

An athlete is given 180 g of glucose $(C_{6} H_{12} O_{6})$ He utilises 50% of the energy due to internal combustion in the body.In order to avoid storage of energy in the body.Calculate the mass of water he would need to perspire.Given enthalpy of combustion of glucose is $- 2800 K J m o l^{- 1}$

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Solution

$180 g$ of glucose is equivalent to $2800 k J$ ${m o l e}^{- 1}$ amount of energy.
But energy utilized $= \frac{50}{100} \times 2800 = 1400 K J {m o l e}^{- 1}$
$∴$ Energy to be given out as prespiration to avoid storage of energy $= 1400 K J {m o l}^{- 1}$
$∴$ mass of water needed to prespire
$= \frac{18}{{Δ H}_{v a p}} \times 1400 = \frac{18}{44} \times 1400 = 572.7 g m$

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