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Standard XII

Physics

Motional EMF

An athlete is...

Question

An athlete is running at a speed of 30 kmh $^{- 1}$ towards east, holding a 3 m metallic rod horizontally. The horizontal component of the earth, magnetic field in this region is $3 \times 10^{- 4}$ Tesla and the angle of dip is 30 $^{o}$ . Then, the emf induced across the ends of the rod is

7.5 mV

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4.3 mV

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zero

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13 mV

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Solution

The correct option is A 4.3 mV
Component of field in the vertical direction = $B_{|} = 3 \times 10^{- 4} t a n (30)$
vertical component of field is perpendicular to both velocity and length of rod
emf = $B_{|} l v = 4.3 m V$

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An athlete is running at a speed of 30 kmh−1 towards east, holding a 3 m metallic rod horizontally. The horizontal component of the earth, magnetic field in this region is 3×10−4 Tesla and the angle of dip is 30o. Then, the emf induced across the ends of the rod is

The correct option is A 4.3 mVComponent of field in the vertical direction = B|=3×10−4tan(30)vertical component of field is perpendicular to both velocity and length of rodemf = B|lv=4.3mV

An athlete is running at a speed of 30 kmh $^{- 1}$ towards east, holding a 3 m metallic rod horizontally. The horizontal component of the earth, magnetic field in this region is $3 \times 10^{- 4}$ Tesla and the angle of dip is 30 $^{o}$ . Then, the emf induced across the ends of the rod is

The correct option is A 4.3 mV
Component of field in the vertical direction = $B_{|} = 3 \times 10^{- 4} t a n (30)$
vertical component of field is perpendicular to both velocity and length of rod
emf = $B_{|} l v = 4.3 m V$