An athlete swims the length of 50 m pool in 20 s and makes the return trip to the starting position in 22 s. Determine his average velocity in
a.The first half of die swim
b.The second half of the swim
c.The round trip

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Solution

(a) Average Velocity $= \frac{T D}{T T} = \frac{50}{20} = 2.5 m / s e c$
(b) Average Velocity $= \frac{T D}{T T} = \frac{50}{22} = 2.2727 m / s e c$
(c) Average Velocity $= \frac{T D}{T T} = \frac{50 + 50}{20 + 22} = 2.38 m / s e c$

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An athlete swims the length of 50 m pool in 20 s and makes the return trip to the starting position in 22 s. Determine his average velocity ina.The first half of die swimb.The second half of the swimc.The round trip

(a) Average Velocity=TDTT=5020=2.5m/sec(b) Average Velocity=TDTT=5022=2.2727m/sec(c) Average Velocity=TDTT=50+5020+22=2.38m/sec

An athlete swims the length of 50 m pool in 20 s and makes the return trip to the starting position in 22 s. Determine his average velocity in
a.The first half of die swim
b.The second half of the swim
c.The round trip

(a) Average Velocity $= \frac{T D}{T T} = \frac{50}{20} = 2.5 m / s e c$
(b) Average Velocity $= \frac{T D}{T T} = \frac{50}{22} = 2.2727 m / s e c$
(c) Average Velocity $= \frac{T D}{T T} = \frac{50 + 50}{20 + 22} = 2.38 m / s e c$