Question

An athlete takes $10$ rounds of a rectangular park, $50\text{m}$ long and $25\text{m}$ wide. Find the total distance covered by him.

Answer 1

Length of the rectangular park $=50\text{m}$
Breadth of the rectangular park $=25\text{m}$
Total distance covered by the athlete in one round will be the perimeter of the park.
Now, perimeter of the rectangular park
$=2\times (\text{length}+\text{breadth})=2\times (50\text{m}+25\text{m})$
$=2\times 75\text{m}=150\text{m}$
So, the distance covered by the athlete in one round is $150\text{m}$.
Therefore, distance covered in $10$ rounds $=10\times 150\text{m}=1500\text{m}$
The total distance covered by the athlete is $1500\text{m}$.