An atom absorbs 2eV energy and is excited to next energy state. The wavelength of light absorbed will be
A
2000A0
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B
4000A0
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C
8000A0
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D
6206A0
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Solution
The correct option is D6206A0 Energy absorbed by atom =2eV Energy of photon should also be nearby 2eV So, Equating the two energies we get: 2eV=4.14×10−15×3×108λ ⇒λ=4.14×3×10−72m ⇒λ=6.21×10−7m⇒λ=6210A∘≈6206A∘