Question

An atom absorbs a photon of wavelength $500nm$ emits another photon of wavelength $700nm$ find the net energy absorbed by the atom in the process

Answer 1

${\lambda }_1=500nm=500\times {10}^{-9}m$

${\lambda }_2=700nm=700\times {10}^{-9}m$

$E_1-E_2$ = Energy absorbed by the atom in the process $=hc\left[1/{\lambda }_1-1/{\lambda }_2\right]$

$=6.63\times 3\left[1/5-1/7\right]\times {10}^{-9}=1.136\times {10}^{-19}J$

We get, $1.136\times {10}^{-19}J.$