An atom has atomic mass 232 and atomic number 90- During the course of disintegration- it emits 2-particles and few -particles- The resultant atom has atomic mass 212 and atomic number 82- How many -particles are emitted during this process-

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Standard XII

Chemistry

Group Displacement Law

An atom has a...

Question

An atom has atomic mass $232$ and atomic number $90$ . During the course of disintegration, it emits $2 β$ -particles and few $α$ -particles. The resultant atom has atomic mass $212$ and atomic number $82$ . How many $α$ -particles are emitted during this process?

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Solution

The decrease in atomic mass $= (232 - 212) = 20$
Decrease in mass occurs due to emission of $α$ -particles. Let $x$ be the number of alpha particles emitted.
Mass of ' $x$ ' $α$ -particles $= 4 x$
So, $4 x = 20$
or $x = \frac{20}{4} = 5$
Alternative method: This can also be determined by the application of the following equation:
Number of $β$ -particles emitted $= 2 \times$ Number of $α$ -particles emitted $- (Z_{P a r e n t} - Z_{E n d p r o d u c t})$
$2 = 2 \times x - (90 - 82)$
or $x = 5$

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An atom has atomic mass 232 and atomic number 90. During the course of disintegration, it emits 2β-particles and few α-particles. The resultant atom has atomic mass 212 and atomic number 82. How many α-particles are emitted during this process?

An atom has atomic mass $232$ and atomic number $90$ . During the course of disintegration, it emits $2 β$ -particles and few $α$ -particles. The resultant atom has atomic mass $212$ and atomic number $82$ . How many $α$ -particles are emitted during this process?