An atom has two electrons more than the noble gas configuration. What type of ion will it form ?

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Solution

let X = 2, 8,2
Atomic number = 12
Valency = +2
It will easily donate $2 e^{-}$ from outermost shell.
${Mg}^{2 +}$ = 12 - 2 = 10.
Element Y is Neon having $10 e^{-}$ as same as ${Mg}^{2 +}$ ion.
Hence the ion formed is cation.

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An atom has two electrons more than the noble gas configuration. What type of ion will it form ?

let X = 2, 8,2Atomic number = 12Valency = +2It will easily donate 2e- from outermost shell.Mg2+ = 12 - 2 = 10.Element Y is Neon having 10e- as same as Mg2+ ion.Hence the ion formed is cation.

let X = 2, 8,2
Atomic number = 12
Valency = +2
It will easily donate $2 e^{-}$ from outermost shell.
${Mg}^{2 +}$ = 12 - 2 = 10.
Element Y is Neon having $10 e^{-}$ as same as ${Mg}^{2 +}$ ion.
Hence the ion formed is cation.