An atom of an element has 3 electrons in 4p subshell. The atomic number of the element is :

31

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33

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35

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34

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Solution

The correct option is C $33$
The electronic configuration of the element which has 3 electrons in 4p subshell, can be written as $[A r] 4 s^{2} 3 d^{10} 4 p^{3}$ . Thus, the atomic number is 33.

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