An atom of an element has 9 electrons with $l = 0$ value, 18 electron with $l = 1$ value and 10 electrons with $l = 2$ . Calculate the atomic number of the element.

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A 37
$l = 0$ corresponds to 's' sub shell, $l = 1$ corresponds to 'p' sub shell, $l = 2$ corresponds to 'd' sub shell. The atom should possess '9' 's' electrons, 18 'p' electrons and 10 'd' electrons.

The electronic configuration of the element should be $1 s^{2} 2 s^{2} 2 p^{6} 3 s^{2} 3 p^{6} 3 d^{10} 4 s^{2} 4 p^{6} 5 s^{1}$

The atomic number of the element should be 37.

Suggest Corrections

Similar questions

Q. A neutral atom of an element has 2K, 8L, 8M and 2N electrons. The total number of electrons present in the orbitals having

l

value 1 are :

Q. An atom of an element has 2,8,11,2 electrons in K, L, M and N shells respectively. The total number of s-electrons in the atom are:

Q. For the element with atomic number 27.Write the electronic configuration.
1) Write down the value of n and l for the electrons in the valence
shell.
2)How many unpaired electrons are present in it.

Q. An atom of an element

(X)

has its

K

L

and

M

shells filled with some electrons. It reacts with sodium metal to from a compound

N a X

. The number of electrons in the

M

shell of the atom

(X)

will be:

An atom of an element (X) has its K, L and M shells filled with some electrons. It reacts with sodium metal to form a compound NaX. The number of electrons in the valence shell of the atom (X) will be

Join BYJU'S Learning Program

An atom of an element has 9 electrons with l=0 value, 18 electron with l=1 value and 10 electrons with l=2. Calculate the atomic number of the element.

An atom of an element has 9 electrons with $l = 0$ value, 18 electron with $l = 1$ value and 10 electrons with $l = 2$ . Calculate the atomic number of the element.