Question

An atom of an element has one unpaired electron in its valence shell. The quantum numbers of the electron could be n = 3 and l = 1. The probable maximum covalencies exhibited by the element could be:

• A. $5,7$
• B. Only $5$
• C. $3,5$
• D. $3,7$

Answer 1

The correct option is D $3,7$

Given that the quantum numbers of the valence electron could be n = 3 and l = 1, the possible electronic configuration can be written as; $3s^{2}3p^1$ and $3s^{2}3p^5$. Therefore the probable maximum covalencies exhibited by the element could be $3$ or $7.$