The correct option is D 6f
Number of radial nodes = n−l−1
where, n is the Principal quantum number and l is the Azimuthal quantum number.
Total number of nodes = n−1
So, n−1 = 5 i.e., n=6
and n−l−1=2 i.e., 6−l−1 = 2
On solving, l=3 which is f - subshell
The atomic orbital is 6f.