Question

An atomic power nuclear reactor can deliver 300 MW. The energy released due to fission of each nucleus of uranium atom $U^{238}$ is 170 MeV. The number of uranium atoms fissioned per hour will be :-

Answer 1

$\begin{array}{c}\frac{N}{t}=\frac{p}{e}=\frac{100\times {10}^6}{170\times {10}^6\times 1.6\times {10}^{-9}}=1.10\times {10}^{-19}\\ N=1.10\times {10}^{19}\times 3600\\ N=3.97\times {10}^{22}\end{array}$