An audio signal vm-20sin2-1500t amplitude modulates a carrier vc-80sin2- 100-000t- The value of percent modulation is

We know that, Modulation index =A_mA_c From given equations, A_m= 20 and nbsp;A_c= 80 nbsp; Percentage modulation index nbsp;=A_mA_c× 100 = 2080× 100 = ...

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Standard XII

Physics

Frequency of a Wave

An audio sign...

Question

An audio signal $v_{m} = 20 sin 2 π (1500 t)$ amplitude modulates a carrier $v_{c} = 80 sin 2 π (100, 000 t)$ . The value of percent modulation is

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Solution

We know that,
Modulation index $= \frac{A_{m}}{A_{c}}$

From given equations, $A_{m} = 20$ and $A_{c} = 80$

Percentage modulation index $= \frac{A_{m}}{A_{c}} \times 100$
$= \frac{20}{80} \times 100 = 25$ %

The value of percent modulation index is $25$ .

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An audio signal vm=20sin2π(1500t) amplitude modulates a carrier vc=80sin2π(100,000t). The value of percent modulation is

We know that, Modulation index =AmAc From given equations, Am=20 and Ac=80 Percentage modulation index =AmAc×100 =2080×100=25% The value of percent modulation index is 25.

An audio signal $v_{m} = 20 sin 2 π (1500 t)$ amplitude modulates a carrier $v_{c} = 80 sin 2 π (100, 000 t)$ . The value of percent modulation is

We know that,
Modulation index $= \frac{A_{m}}{A_{c}}$

From given equations, $A_{m} = 20$ and $A_{c} = 80$

Percentage modulation index $= \frac{A_{m}}{A_{c}} \times 100$
$= \frac{20}{80} \times 100 = 25$ %

The value of percent modulation index is $25$ .