An audio signal vm-20sin2-1500t amplitude modulates a carrier vc-80sin2- 100-000t- The value of percent modulation is

We know that, Modulation index =A_mA_c From given equations, A_m= 20 and nbsp;A_c= 80 nbsp; Percentage modulation index nbsp;=A_mA_c× 100 = 2080× 100 = ...

You visited us 6 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XII

Physics

Frequency of a Wave

An audio sign...

Question

An audio signal $v_{m} = 20 sin 2 π (1500 t)$ amplitude modulates a carrier $v_{c} = 80 sin 2 π (100, 000 t)$ . The value of percent modulation is

Open in App

Solution

We know that,
Modulation index $= \frac{A_{m}}{A_{c}}$

From given equations, $A_{m} = 20$ and $A_{c} = 80$

Percentage modulation index $= \frac{A_{m}}{A_{c}} \times 100$
$= \frac{20}{80} \times 100 = 25$ %

The value of percent modulation index is $25$ .

Suggest Corrections

Similar questions

Q. An audio signal represented as

25 sin 2 π (2000 t)

amplitude modulated by a carrier wave:

60 sin 2 π (100, 000 t)

. The modulation index of the modulated signal is

Q. An audio signal

15 s i n 2 π (1500) t

amplitude modulates

60 s i n 2 π (10^{5}) t

. The depth of modulation is:

Q. (a) Give three reasons why modulation of a message signal necessary for long distance transmission.
(b) Show graphically an audio signal, a carrier wave and an amplitude modulated wave.

Q. What is the modulation index if an audio signal of amplitude one-half of the carrier amplitude is used in AM?

Q. An audio signal of

V_{m} = 5 s i n 6 π \times 10^{3} t

is to be modulated on a carrier wave given by

V_{c} = 5 s i n 2 π \times 10^{5} t

. The frequencies of the side bands and bandwidth are

Join BYJU'S Learning Program

An audio signal vm=20sin2π(1500t) amplitude modulates a carrier vc=80sin2π(100,000t). The value of percent modulation is

We know that, Modulation index =AmAc From given equations, Am=20 and Ac=80 Percentage modulation index =AmAc×100 =2080×100=25% The value of percent modulation index is 25.

An audio signal $v_{m} = 20 sin 2 π (1500 t)$ amplitude modulates a carrier $v_{c} = 80 sin 2 π (100, 000 t)$ . The value of percent modulation is

We know that,
Modulation index $= \frac{A_{m}}{A_{c}}$

From given equations, $A_{m} = 20$ and $A_{c} = 80$

Percentage modulation index $= \frac{A_{m}}{A_{c}} \times 100$
$= \frac{20}{80} \times 100 = 25$ %

The value of percent modulation index is $25$ .