Question

An auditorium has volume of 10${}^5$ m${}^3$ and surface area of absorption 2 X10 ${}^4$m${}^2$ . Its average absorption coefficient is 0.2. The reverberation time of the auditorium in seconds is

• A. 6.5
• B. 5.5
• C. 4.25
• D. 3.25

Answer 1

The correct option is C 4.25

Reverberation time$=0.161\frac{v}{a\times c}$
$=\frac{0.161\times {10}^5}{2\times {10}^4\times 0.2}$
$=4.025seconds$