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Question

An automobile engine develops 100KW when rotating at a speed of 1800 rev/min. The torque it delivers (in N-m)

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Solution

It is given that
Power of the engine,
P=100kW=100000W

Angular speed,
ω=1800rev/min

Now, we know that
Power=Torque×AngularSpeed
100000=Torque×60π
Torque=530.78Nm

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