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Byju's Answer
Standard XII
Physics
Force Couple
An automobile...
Question
An automobile engine develops 100KW when rotating at a speed of 1800 rev/min. The torque it delivers (in N-m)
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Solution
It is given that
Power of the engine,
P
=
100
k
W
=
100000
W
Angular speed,
ω
=
1800
r
e
v
/
m
i
n
Now, we know that
P
o
w
e
r
=
T
o
r
q
u
e
×
A
n
g
u
l
a
r
S
p
e
e
d
→
100000
=
T
o
r
q
u
e
×
60
π
→
T
o
r
q
u
e
=
530.78
N
m
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