Question

An automobile engine develops a power of $100$ kilowatt, when rotating at a speed of $30rev/sec$. What torque does it deliver?

• A. $\frac{1000}{3\pi }N-m.$
• B. $\frac{2000}{3\pi }N-m.$
• C. $\frac{5000}{3\pi }N-m.$
• D. $\frac{4000}{3\pi }N-m.$

Answer 1

The correct option is C $\frac{5000}{3\pi }N-m.$

power=torque$\times \omega$

$100k=T\times 30\times 2\pi$

$T=\frac{5000}{3\pi }$N-m