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Question

An automobile engine propels a 1000 kg car (A) along a lavelled road at a speed of 36 kmh–1. Find the power if the opposing frictional force is 100 N. Now, suppose after travelling a distance of 200 m, this car collides with another stationary car (B) of same mass and comes to rest. Let its engine also stop at the same time. Now car (B) starts moving on the same level road without getting its engine started. Find the speed of the car (B) just after the collision.

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Solution

Dear Student,
Power of the car =Force ×speed =100×36×5/18=1000J/sAssuming collision is elastic then the speed of car B will be same as car A because car comes in rest after collision .Regards

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