An automobile wheel has a radius of 35 cm. How many revolutions will it make to cover a distance of 11 kilometres?

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Solution

$G i v e n t h a t t h e r a d i u s r o f t h e w h e e l = 35 c m = 35 \times 10^{- 5} k m ∴ i t s c i r c u m f e r e n c e C = 2 π r w h e n π = \frac{22}{7} . S o C = 2 \times \frac{22}{7} \times 35 \times 10^{- 5} k m = 220 m . T h e d i s t a n c e t h e a u t o m o b i l e t r a v e l l s = 11 k m . I n o n e r e v o l u t i o n t h e w h e e l c a n c o v e r a d i s t a n c e d = i t s c i c u m f e r e n c e C . S o t h e n u m b e r o f r e v o l u t i o n s n t o c o v e r a d i s t a n c e d = \frac{d}{C} . i . e n = \frac{11}{220 \times 10^{- 5}} = 5000. A n s - t h e n u m b e r o f r e v o l u t i o n s t h e w h e e l w i l l m a k e = 5000 .$

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