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Question
An average emf of 20 V is induced in an inductor when the current in it is changed from 2.5 A in one direction to 5.5 A in the opposite direction, in 0.1 s. Find the self-inductance of the inductor.
An average emf of 20 V is induced in an inductor when the current in it is changed from 2.5 A in one direction to 5.5 A in the opposite direction, in 0.1 s. Find the self-inductance of the inductor.
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Solution
The correct option is C 0.25 H
Given:
E=20 V
dI=I2−I1=(−5.5)−2.5=−8 A
dt=0.1 s
Now,
E=−LdIdt
⇒20=−L−80.1
⇒L=0.25 H
Given:
E=20 V
dI=I2−I1=(−5.5)−2.5=−8 A
dt=0.1 s
Now,
E=−LdIdt
⇒20=−L−80.1
⇒L=0.25 H
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