Question

An column section ISHB 350 @ 674/m carries an axial load of 1100 kN. Given,
${\sigma }_c=4N/m{m}^2$
length of base plate = 550 mm.
If it is subjected to a bending moment of 60 kN-m, what will be the width of base plate _______.

• A. 648 mm
• B. 800 mm
• C. 767 mm
• D. 538 mm

Answer 1

The correct option is B 800 mm

P = 1100 kN, M = 60 kN-m

$e=\frac{M}{P}=\frac{60\times {10}^3}{1100}=54.54mm$

$\frac{e}{L}=\frac{54.54}{550}=\frac{1}{10.08}<\frac{1}{6}$

Hence width of base

$=\frac{P}{{\sigma }_{c}L}(1+\frac{6e}{L})$

$=\frac{1100\times {10}^3}{4\times 550}(1+\frac{6\times 54.54}{550})$

= 797.49 mm

= 800 mm