Question

An $\alpha -particle$ is bombarded on ${}_7{N}^{14}$. As a result a ${}_8{0}^{17}$ nucleus is formed and a particle is emitted This particle is :

• A. neutron
• B. proton
• C. electron
• D. positron

Answer 1

Answer: (B)

proton

$\begin{array}{c}\text{According to question.}\\ {}_2^{4}He+{}_7^{14}N⟶{}_8^{17}O+{}_a^{b}x\end{array}$

$\begin{array}{c}\text{atomic no. and mass is balaced both side}\\ {\therefore }_b^{a}x{=}_1^{1}x\end{array}$

$\begin{array}{cc}& a=1,b=1\\ \therefore & x\text{is hydrogen.}\end{array}$

$\begin{array}{c}\text{Hydrgen only have proton, it does not have}\\ \text{any neutron.}\end{array}$

$\begin{array}{c}\text{The particle emitted must be proton}\\ \text{(B) Proton is correct option.}\end{array}$