The correct option is A Angular momentum
Orbital speed of a satellite of mass m revolving around a planet of mass M in the orbit of radius r is given by,v=√GMrso, v∝1√r, means as r, increases v decreases.
Angular momentum of the satellite:
L=mvr=m(√GMr)r
So, L∝√r, means as r increases, L also increases.
Kinetic Energy of the satellite:
K=GMm2r
So, K∝1r, means as r increases, K decreases.
Angular velocity:
ω=vr=√(GMr)r∝1r32
So, as r increases, ω decreases.
Hence, only the angular momentum increases with the increase in the radius of the circular orbit. So, option (a) is the correct answer.