Question

An earth satellite $S$ has an orbit radius which is $4$ times that of a communication satellite $C$. The period of revolution of $S$ is

• A. 4 days
• B. 8 days
• C. 16 days
• D. 32 days

Answer 1

The correct option is B 8 days

We know,
$T^2\propto R^3$
$R_S=4R_C$

$\frac{T_C^2}{R_C^3}=\frac{T_S^2}{R_S^3}$

$\frac{1^2}{R_C^3}=\frac{T_S^2}{64R_C^3}$

$T_S^2=64$

$T_S=8$ days