An effort of 20 kgf is applied on a machine through a distance of 80 cm, when a load of 30 kgf moves through a distance of 1 cm. Calculate the mechanical advantage of the machine.

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1.5

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Solution

The correct option is C 1.5
Mechanical advantage $= \frac{l o a d}{e f f o r t}$
$= \frac{30 k g f}{20 k g f} = 1.5$

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