An effort of 240 N overcome a useful load 1000 N when applied to a block and system of pulleys; such that the weight movable block and friction is 200 N. What is the efficiency of the system?

81.4%

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82%

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83.4%

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84%

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Solution

The correct option is C
83.4%

Give: Load = 1000 N, effort = 240 N and friction = 200 N
Mechanical advantage $= \frac{L o a d}{E f f o r t} = \frac{1000}{240} = 4.17$

Velocity ratio = Ideal mechanical advantage
$= \frac{R e s i s t a n c e o v e r c o m e}{E f f o r t}$
$= \frac{U s e f u l l o a d + o t h e r f o r c e}{E f f o r t}$
$= \frac{1000 + 200}{240} = \frac{1200}{240} = 5$

Efficiency $= \frac{M A}{V R} \times 100 = \frac{4.16}{5} \times 100 = 83.4 %$

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An effort of 240 N overcome a useful load 1000 N when applied to a block and system of pulleys; such that the weight movable block and friction is 200 N. What is the efficiency of the system?

The correct option is C 83.4% Give: Load = 1000 N, effort = 240 N and friction = 200 N Mechanical advantage =LoadEffort=1000240=4.17 Velocity ratio = Ideal mechanical advantage =Resistance overcomeEffort =Useful load+other forceEffort =1000+200240=1200240=5 Efficiency =MAVR×100=4.165×100=83.4%