An effort of $26 N$ is applied to a simple machine with the mechanical advantage of $10$ to lift an object. Calculate the weight of the object.

Open in App

Solution

Step 01:
The mechanical advantage of the machine (MA) $= 10$
Effort applied $= 26 N$
Let the load balanced $= x N$
Step 02: Calculation:
Since we know MA can be given as,
$M A (m e c h a n i c a l a d v a n t a g e) = \frac{L o a d}{E f f o r t}$
Substituting the value of MA and Effort we get,
$10 = \frac{x}{26 N} x = 26 \times 10 = 260 N S i n c e x = m g (m = m a s s, g = 10 m s^{- 2} = a c c e l e r a t i o n d u e t o g r a v i t y) \Rightarrow m = \frac{260 N}{10 m s^{- 2}} m = 26 k g$
Hence the weight of the object is $26 k g .$

Suggest Corrections

Similar questions

Determine the mechanical advantage of a simple machine which helps to lift a load of $75 k g f$ when an effort of $15 k g f$ is applied.

Calculate the mechanical advantage of a simple machine that can lift a load of $200 N$ with an effort of $50 N .$

In a machine, an effort of $10 k g f$ is applied to lift a load of $100 K g f$ . What is the mechanical advantage of the machine?

In a machine, an effort of 10 N is applied to lift a load of 100 N. What is its mechanical advantage?

A machine has a mechanical advantage of $10$ . It used to lift a load of $200 k g f$ . Find the required effort.

Join BYJU'S Learning Program