An effort of 50 kgf is applied at the end of a lever of the second order which supports a load of 750 kgf. Find the mechanical advantage?

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Solution

Step 1:
Given data,
Load = 750 kgf,
Effort = 50 kgf
Step 2:
Formula:
$M e c h a n i c a l a d v a n t a g e = \frac{L o a d}{E f f o r t}$
Step 3:
Substitute the values in the above formula
$M e c h a n i c a l a d v a n t a g e = \frac{750}{50} = 15$
Hence, the mechanical advantage is 15.

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An effort of 50 kgf is applied at the end of a lever of the second order which supports a load of 750 kgf. Find the mechanical advantage?

Step 1:Given data,Load = 750 kgf,Effort = 50 kgfStep 2:Formula:Mechanicaladvantage=LoadEffortStep 3:Substitute the values in the above formulaMechanicaladvantage=75050=15Hence, the mechanical advantage is 15.

Step 1:
Given data,
Load = 750 kgf,
Effort = 50 kgf
Step 2:
Formula:
$M e c h a n i c a l a d v a n t a g e = \frac{L o a d}{E f f o r t}$
Step 3:
Substitute the values in the above formula
$M e c h a n i c a l a d v a n t a g e = \frac{750}{50} = 15$
Hence, the mechanical advantage is 15.