You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XII

Physics

COE in SHM

An elastic sp...

Question

An elastic spring is compressed between two blocks of masses 1 kg and 2 kg resting on a smooth horizontal table as shown. If the spring has 12 J of energy and suddenly released, the velocity with which the larger block of 2 kg moves will be

2 m/s

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

4 m/s

No worries! We‘ve got your back. Try BYJU‘S free classes today!

1 m/s

No worries! We‘ve got your back. Try BYJU‘S free classes today!

8 m/s

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A 2 m/s
Using momentum conservation
$m_{A} . v_{A} = m_{B} v_{B}$
$\Rightarrow v_{A} = 2 v_{B}$
Now total $K . E = P . E$ of spring

$\frac{1}{2} m_{A} v_{A}^{2} + \frac{1}{2} m_{B} {(V_{B})}_{B}^{2} = 12$

$\frac{1}{2} m_{A} \times 4 V_{B}^{2} + \frac{1}{2} m_{B} (V_{B})^{2} = 12$

$3 {(v_{B})}_{B}^{2} = 12$
$v_{B} = 2 m / s$

Suggest Corrections

Similar questions

Q. A light spring of force constant

K

is held between two blocks of masses

m

and

2 m

. The two blocks and the spring system rests on a smooth horizontal floor. Now the blocks are moved towards each other compressing the spring by

x

and then they are suddenly released. The relative velocity between the blocks when the spring attains its natural length will be

Q. A block of mass

2 k g

is on a smooth horizontal surface. A light spring of force constant

800 N / m

has one end rigidly attached to a vertical wall and lying on that horizontal surface. Now the block is moved towards the wall compressing the spring over a distance of

5 c m

and then suddenly released. By the time the spring regains its natural length and breaks contact with the block, the velocity acquired by the block will be :

Q. Two blocks of masses of

3

kg and

6

kg rest on a horizontal smooth surface. The

3

kg block is attached to a spring with a force constant

k = 900 N m^{- 1}

which is compressed

2

m beyond the equilibrium position. The

6

kg mass is at rest at

1

m from mean position,

3

kg mass strikes the

6

kg mass and the two stick together

Q. A block of mass

M = 4 kg

is kept on a smooth horizontal plane. A bar of mass

m = 1 kg

is kept on it. They are connected to a spring as shown and the spring is compressed. Then, what is the maximum compression in the spring for which the bar will not slip on the block when released, if coefficient of friction between them is

0.2

and spring constant

= 1000 N/m

(Take

g = 10 {m/s}^{2}

)

The ends of spring are attached to blocks of mass 3 kg and 2 kg. The 3 kg block rests on a horizontal surface and the 2 kg block which is vertically above it is in equlibirium producing a compression of 1 cm Of the spring . The 2 kg mass must be compressed further by at least______, So that when it is released, the 3kg block may be lifted off the ground.

Join BYJU'S Learning Program

An elastic spring is compressed between two blocks of masses 1 kg and 2 kg resting on a smooth horizontal table as shown. If the spring has 12 J of energy and suddenly released, the velocity with which the larger block of 2 kg moves will be

The correct option is A 2 m/sUsing momentum conservationmA.vA=mBvB⇒vA=2vBNow total K.E=P.E of spring12mAv2A+12mB(VB)2=1212mA×4V2B+12mB(VB)2=123(vB)2=12vB=2m/s