You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XII

Chemistry

Characteristics of Equilibrium Constant

An elastic sp...

Question

An elastic spring of unstretched length $L$ and force constant $K$ is stretched by a small length $x$ . It is further stretched by another small length $y$ . Work done during the second stretching is

\frac{k y}{2} (x + 2 y)

No worries! We‘ve got your back. Try BYJU‘S free classes today!

\frac{k}{2} (x + 2 y)

No worries! We‘ve got your back. Try BYJU‘S free classes today!

k y (x + 2 y)

No worries! We‘ve got your back. Try BYJU‘S free classes today!

\frac{k y}{2} (2 x + y)

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is C $\frac{k y}{2} (2 x + y)$
$w o r k d o n e = c h a n g e i n P E = \frac{k}{2} ({(x + y)}^{2} - x^{2}) = \frac{k y}{2} (2 x + y)$

Suggest Corrections

Similar questions

Q. An elastic spring of unstretched length

L

and force constant

K

, is stretched by a small length

x

. It is further stretched by another small length

y

. calculate the work done during the second stretching is:

Q. A spring of unstretched length

l

and force constant

k

is stretched by a small length

x

. It is further stretched by another small length

y

. The work done in the second stretching is

Q. A spring of unstretched length

l

and force constant

k

is stretched by a small length

x

. It is further stretched by another small length

y

. The work done in the second stretching is

Q. An elastic string of unstretched length

^{'} L^{'}

and force constant

^{'} k^{'}

is stretched by a small length

^{'} x^{'}

. It is further stretched by small length

^{'} y^{'}

. The work done in the second stretching is

an elastic spring of unstretched lenght L and force constant K is stretched by a small length C it is further stretched by a small length Y the qork done in seconh stretching is

Join BYJU'S Learning Program

An elastic spring of unstretched length L and force constant K is stretched by a small length x. It is further stretched by another small length y. Work done during the second stretching is

The correct option is C ky2(2x+y)workdone=changeinPE=k2((x+y)2−x2)=ky2(2x+y)

An elastic spring of unstretched length $L$ and force constant $K$ is stretched by a small length $x$ . It is further stretched by another small length $y$ . Work done during the second stretching is

The correct option is C $\frac{k y}{2} (2 x + y)$
$w o r k d o n e = c h a n g e i n P E = \frac{k}{2} ({(x + y)}^{2} - x^{2}) = \frac{k y}{2} (2 x + y)$