An electric bulb and a capacitor, are connected in series with an AC source. On increasing the frequency of the source, the brightness of the bulb will:
A
Increase
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
Decrease
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
Remain unchanged
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
increase or decrease, depending upon the resistance of the bulb
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is A Increase In an RC circuit, the brightness of the bulb depends upon the power delivered to it, so,
⇒Pout=(ErmsZ)R
Here, Z=√R2+(1ωC)2
As ω is increased, Z decreases, so that, Pout increases. So, the brightness of the bulb will increase.