An electric bulb and a capacitor are connected in series with an AC source. On increasing the frequency of the source, the brightening of the bulb will,
A
increase
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B
decrease
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C
remain unchanged
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D
sometimes increase and sometimes decrease
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Solution
The correct option is A increase
P=I2R=(ErmsZ)2R
Here, Z=√R2+X2C=√R2+(1ωC)2
As ω is increased, Z decreases, so that, P increases. So, the brightness of the bulb will also increase.