An electric bulb having small resistance and a capacitor are joined in series with an AC source whose frequency can be varied. On increasing the frequency of AC source, the glow of the bulb
A
increases.
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B
decreases.
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C
remains unchanged.
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D
The bulb will not glow at all.
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Solution
The correct option is A increases. We know that, when a capacitor of capacitance (C) is connected across an AC supply of voltage E=E0sin(ωt), then current in the circuit is i=E0ωCsin(ωt+π/2).
⇒i∝ω
Therefore, current increases when the frequency of the AC source is increased, which in turn increases the glow of the bulb.