An electric bulb is rated $100 W$ at $220 V$ . When it is connected to $110 V$ main supply, the power consumed would be:

100 W

No worries! We‘ve got your back. Try BYJU‘S free classes today!

75 W

No worries! We‘ve got your back. Try BYJU‘S free classes today!

50 W

No worries! We‘ve got your back. Try BYJU‘S free classes today!

25 W

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is D $25 W$
Resistance of bulb $= \frac{V^{2}}{P} = \frac{220^{2}}{100} = 484 Ω$
When supply is $110 V$ , then power consumed $= \frac{V^{2}}{R} = \frac{110^{2}}{484} = 25 W$

Suggest Corrections

Similar questions

An electric bulb is rated 220 V and 100 W. When it is operated on 110 V, the power consumed is:

An electric bulb is rated 220 V and 100 W. Power consumed by it operated on 110 V is

A 100W electric bulb is connected to 220V main power supply. Calculate the strength of electric currect passing through the bulb. If the same bulb is taken to USA where the main power supply is 110V, how much electric current will pass through the bulb when connected to mains?

Three bulbs labelled 100W 220V, 50W 220V, 200W 220V are connected in series across a 220V power supply. Calculate the total power consumed by the bulbs.

Q. Two electric bulbs marked

25 W - 220 V

and

100 W - 220 V

are connected in series to a

440 V

supply. Which of the bulbs will fuse?

Join BYJU'S Learning Program

An electric bulb is rated 100W at 220V. When it is connected to 110V main supply, the power consumed would be:

The correct option is D 25WResistance of bulb =V2P=2202100=484ΩWhen supply is 110V, then power consumed =V2R=1102484=25W

An electric bulb is rated $100 W$ at $220 V$ . When it is connected to $110 V$ main supply, the power consumed would be:

The correct option is D $25 W$
Resistance of bulb $= \frac{V^{2}}{P} = \frac{220^{2}}{100} = 484 Ω$
When supply is $110 V$ , then power consumed $= \frac{V^{2}}{R} = \frac{110^{2}}{484} = 25 W$