An electric bulb is rated $200 V - 100 W$ . Find the resistance of the bulb.

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Solution

Characteristics of the bulb is given as $V = 200$ volts and $P = 100$ watt
Resistance of the bulb $R = \frac{V^{2}}{P}$
$∴$ $R = \frac{(200)^{2}}{100} = 400 Ω$

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An electric bulb is rated 200V−100W. Find the resistance of the bulb.

Characteristics of the bulb is given as V=200 volts and P=100 wattResistance of the bulb R=V2P∴ R=(200)2100=400Ω

An electric bulb is rated $200 V - 100 W$ . Find the resistance of the bulb.

Characteristics of the bulb is given as $V = 200$ volts and $P = 100$ watt
Resistance of the bulb $R = \frac{V^{2}}{P}$
$∴$ $R = \frac{(200)^{2}}{100} = 400 Ω$