An electric bulb is rated 220 V and 100 W. When it is operated on 110 V, the power consumed will be:
25 W
Let's find the resistance value of the bulb when it is operated under the rated conditions.
P = V2R
R = V2P = 2202100
Now, when the bulb is operated across 110 V then Power = 1102R
Hence, P = 25 W