An electric bulb is rated 220 V and 100 W . When it is operated on 110 V , what will be the power consumed ??

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Solution

P = V²/R
If V = 220 V we have

100 W = 220²/R
R = 220²/100 Ω = 484 Ω. This is the resistance of the bulb.

When V = 110 V, power consumed = V²/R = 110² /484 = 25 W.

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