An electric bulb is rated 220V and 100W. When it is operated on 110V, the power consumed will be-

a) 25W

b) 50W

c) 75W

d) 100W

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Solution

P = V2/R
If V = 220 V we have

100 W = 2202/R
R = 2202/100 Ω = 484 Ω. This is the resistance of the bulb.

When V = 110 V, power consumed = V2/R = 1102 /484 = 25 W.

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