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Question

An electric bulb marked 220 V, 100 W will get fused if it is made to consume 150 W or more. What voltage fluctuation will the bulb withstand?

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Solution

Given that the operating voltage is V and power consumed is P.
Therefore, the resistance of the bulb,
R=V2P=(220×220)100=484 Ω
The power fluctuation, p = 150 W. So, the voltage fluctuation that the bulb can withstand,
v=pR=150×484 =269.4 V=270 V
The bulb will withstand up to 270 V.

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