An electric bulb of $60 W$ is used for $6 h r s / d a y$ . Calculate the units of energy consumed in one day by the bulb.

0.18 units

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0.36 units

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0.54 units

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0.72 units

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Solution

The correct option is B $0.36 units$
Given : $t = 6 h r s$
$P = 0.06 k W$
Thus energy consumed per day is:
$E = P t = 0.06 \times 6 = 0.36 k W h$ $= 0.36 units$

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