An electric bulb of resistance 20 - draws a current of 0-04 A- Calculate the potential difference at the ends-

The correct option is C 0.8 V Given,Resistance of resistor R = 20 #160; Ω Current draws #160; #160;I = 0.04 #160; A According to ohm's ...

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Standard X

Physics

Electric Power

An electric b...

Question

An electric bulb of resistance $20 Ω$ draws a current of $0.04 A$ . Calculate the potential difference at the ends.

0.8 V

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2 V

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0.032 V

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5 V

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Solution

The correct option is C $0.8 V$
Given,
Resistance of resistor $R = 20 Ω$
Current draws $I = 0.04 A$
According to ohm's law
Potential difference, $V = I R = 0.04 \times 20 = 0.8 V$ .
Hence Option A

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An electric bulb of resistance 20Ω draws a current of 0.04A. Calculate the potential difference at the ends.

The correct option is C 0.8VGiven,Resistance of resistor R=20ΩCurrent draws I=0.04AAccording to ohm's lawPotential difference, V=IR=0.04×20=0.8V.Hence Option A

An electric bulb of resistance $20 Ω$ draws a current of $0.04 A$ . Calculate the potential difference at the ends.

The correct option is C $0.8 V$
Given,
Resistance of resistor $R = 20 Ω$
Current draws $I = 0.04 A$
According to ohm's law
Potential difference, $V = I R = 0.04 \times 20 = 0.8 V$ .
Hence Option A