Question

An electric bulb of resistance 280 $\Omega$ is connected to 200 Volt supply line. The peak value of current flowing in the circuit will be

• A. nearly 1 amp
• B. zero
• C. nearly 2 amp
• D. nearly 4 amp

Answer 1

Answer: (A)

nearly 1 amp

$V_{peak}={\sqrt{2}V}_{rated}$

$I_{peak}=\frac{V_{peak}}{R}$
$=\frac{\sqrt{2}\times 200}{280}=1A$