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Question
An electric bulb of resistance 500Ω draws current 0.4 A from the source. Calculate: (a) the power of bulb and (b) the potential difference at its end.
An electric bulb of resistance 500Ω draws current 0.4 A from the source. Calculate: (a) the power of bulb and (b) the potential difference at its end.
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Solution
(a)
Power = I2×R =0.4×0.4×500=80 watt
(b)
Potential drop (v)= I × R= 0.4×500=200 V
(a)
Power = I2×R =0.4×0.4×500=80 watt
(b)
Potential drop (v)= I × R= 0.4×500=200 V
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