Question

An electric bulb of resistance of $1000\Omega$ draws a current of $0.05A$. Calculate the power of the bulb :

• A. $500W$
• B. $25kW$
• C. $250W$
• D. $650W$

Answer 1

The correct option is C $250W$

Given: $Resistance\left(R\right)=1000\Omega ,Current\left(I\right)=0.5A$
We know that, Power $P=I^2\cdot R={\left(0.5A\right)}^2\times \left(1000\right)\Omega =250W$.